On 3/18/20 8:46 PM, LIU Zhiwei wrote:
> +static inline int32_t asub32(CPURISCVState *env, int vxrm, int32_t a,
> int32_t b)
> +{
> + int64_t res = (int64_t)a - b;
> + uint8_t round = get_round(vxrm, res, 1);
> +
> + return (res >> 1) + round;
> +}
> +
>
> I find a corner case here. As the spec said in Section 13.2
>
> "There can be no overflow in the result".
>
> If the a is 0x7fffffff, b is 0x80000000, and the round mode is round to
> up(rnu),
> then the result is (0x7fffffff - 0x80000000 + 1) >> 1, equals 0x80000000,
> according the v0.7.1
That's why we used int64_t as the intermediate type:
0x000000007fffffff - 0xffffffff80000000 + 1
= 0x000000007fffffff + 0x0000000080000000 + 1
= 0x00000000ffffffff + 1
= 0x0000000100000000
Shift that right by 1 and you do indeed get 0x80000000.
There's no saturation involved.
For int64_t we computed signed overflow to do the same thing.
r~
