Subba Rao writes:
> On 0, Sam <[EMAIL PROTECTED]> wrote:
> > >
> > > The OR operator ( || ) is for 2 expressions. The correct syntax should be
> > >
> > > if(^/(To|Cc): .*(jack|bob).*/ ){
> > > to "!jack bob"
> > > }
> >
> > Congratulations. Any time either jack or bob receives a message, both of
> > them will now receive a copy of it.
> >
> > That's not what the guy wants.
> >
>
> Ok here it is.
>
> if(^/(To|Cc): .*(jack&bob).*/ ) {
> to "!jack bob"
> }
When there's a To: or Cc: header that contains the string 'jack&bob',
verbatim, forward the message to both of them.
& carries no special meaning in regular expressions.
> if(^/(To): .*(jack|bob).*/ && ^/Cc: .*(jack|bob).*/ ) {
> to "!jack bob"
> }
If there's a To: header containing either jack, or bob, and that there is a
Cc: header containing either jack, or bob, forward the message to both of
them.
According to these rules, if a message contains the following header:
To: jack, bob
The message will be discarded, because it meets neither conditions.
What you really want to do is very simple:
if (hasaddr("[EMAIL PROTECTED]"))
{
cc "! jack"
}
if (hasaddr("[EMAIL PROTECTED]"))
{
cc "! bob"
}
# Rest of the filtering instructions
