> This is a little tricky for the deparser. It sees a call to a function > which was determined by an expression. Sometimes you want parens, sometimes > you don't. For example, if getfun(y) returns a function, it's clearer to > display a call as getfun(y)(x) than (getfun(y))(x). > > I'll see if I can work out which kinds of expressions need to be > parenthesized and implement it in the deparser.
I suspect it's only when you have a function in the quoted call, not a symbol: # Don't add parens q1 <- quote(g(f)(x)) is.symbol(q1[[1]]) # Add parents q2 <- substitute(f(x), list(f = function(x) {x + 1})) is.function(q2[[1]]) Thanks for thinking about it! Hadley -- Chief Scientist, RStudio http://had.co.nz/ ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel