The last one worked! The other one, not.
Thank you very much!
Another question about merge(): sometimes I'm merging two
dataframes and the merged dataframe has much more rows
than the two merged? I think this should not happen,does
it?
Cecília
Em Fri, 20 Aug 2010 09:37:26 -0400
Gabor Grothendieck <ggrothendi...@gmail.com> escreveu:
On Fri, Aug 20, 2010 at 9:33 AM, Gabor Grothendieck
<ggrothendi...@gmail.com> wrote:
On Fri, Aug 20, 2010 at 9:27 AM, Cecilia Carmo
<cecilia.ca...@ua.pt> wrote:
It wasn't the merge command. It doesn't create the
variable x3.
Cecília
How about:
x$k3 <- with(x, unlist(tapply(k1, k1, seq_along)))
y$k3 <- with(y, unlist(tapply(k1, k1, seq_along)))
And here is a second one in case that one overflows as
well:
x$k3 <- with(x, seq_along(k1) - match(k1, k1) + 1)
y$k3 <- with(y, seq_along(k1) - match(k1, k1) + 1)
Note that this one assumes that the data frame is sorted
by k1 which
in your example it is.
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