Dear R-help-list
I have two character vectors
a <- c("A", "B", "C")
b <- c("A", "C", "B")
Then
sapply(a, function(i) grep(i, b))
computes the permutation of the entries in 'b' needed
to bring 'b' into the same order as 'a'.
I have searched around, but haven't been able to find
any existing function that compute this permutation.
Is there such a function doing this -- perhaps more
efficiently than the above?
For those interested, I need the permutation to bring
the rows of a data frame into the same order as the
levels of a factor.
Thanks, Niels
--
Niels Richard Hansen Web: www.math.ku.dk/~richard
Associate Professor Email: niels.r.han...@math.ku.dk
Department of Mathematical Sciences nielsrichardhan...@gmail.com
University of Copenhagen Skype: nielsrichardhansen.dk
Universitetsparken 5 Phone: +45 353 20783 (office)
2100 Copenhagen Ø +45 2859 0765 (mobile)
Denmark
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