On Sep 16, 2010, at 4:23 AM, Michael Bedward wrote:
match(b, a) ?
Or just order(.) : b[order(a)] [1] "A" "C" "B" -- David
Michael On 16 September 2010 17:13, Niels Richard Hansen <niels.r.hansen+li...@math.ku.dk> wrote:Dear R-help-list I have two character vectors a <- c("A", "B", "C") b <- c("A", "C", "B") Then sapply(a, function(i) grep(i, b)) computes the permutation of the entries in 'b' needed to bring 'b' into the same order as 'a'. I have searched around, but haven't been able to find any existing function that compute this permutation. Is there such a function doing this -- perhaps more efficiently than the above? For those interested, I need the permutation to bring the rows of a data frame into the same order as the levels of a factor. Thanks, Niels --
David Winsemius, MD West Hartford, CT ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
