Hi Gregory, May be this?
# some data set.seed(123) x <- factor(sample(0:1, 20, TRUE)) x # [1] 0 1 0 1 1 0 1 1 1 0 1 0 1 1 0 1 0 0 0 1 # Levels: 0 1 as.numeric(as.factor(x)) # [1] 1 2 1 2 2 1 2 2 2 1 2 1 2 2 1 2 1 1 1 2 as.numeric(as.character(x)) [1] 0 1 0 1 1 0 1 1 1 0 1 0 1 1 0 1 0 0 0 1 HTH, Jorge On Mon, Sep 20, 2010 at 10:40 PM, Gregory Ryslik <> wrote: > Hm, > > Now that you mention it, I believe they are factors. They just appeared as > 0 or 1 so I treated them as numbers. > > Once I found out they were factors I tried using the as.numeric() but that > makes it 1 or 2 as before. How do I actually make it keep the factor number? > > Thanks, > Greg > On Sep 20, 2010, at 10:28 PM, David Winsemius wrote: > > > > > On Sep 20, 2010, at 10:12 PM, Gregory Ryslik wrote: > > > >> Hi, > >> > >> I have a list of 5 main elements where each main element has 247 atomic > entries either 0 or 1. I need to get this into a 247x5 matrix so I do > "do.call(cbind, mylist)". However, it renumbers 0 to a 1 and the 1 to a 2 > so that my matrix is filled with 1's and 2's. > >> > > > > If I had such a problem I would see if this were more effective: > > > > matrix(unlist(mylist), length(mylist[[1]]) ) > > > > (There is the column major order default of R matrices.) > > > >> I understand I can fix it in this case by doing a replace but I would > like to avoid that step. Further, sometimes, my list entries will be from 0 > to n. I don't want to have to always renumber all the possibilities. > >> > >> I'm not quite sure why this is going on because when I build the > following: l <- list(c(1,2,3),c(1,2,3),c(1,2,3)) > >> and execute do.call(cbind, l) it works just fine and there is no > renumbering! > > > > I wouldn't have expected it either, but you only provided an example of > what did work. My attempt at reproducing your problem also failed: > > > > > ll <- list(a=c(1,0,1,1,0), b=c(0,1,0,0,1) ) > > > do.call(cbind, ll) > > a b > > [1,] 1 0 > > [2,] 0 1 > > [3,] 1 0 > > [4,] 1 0 > > [5,] 0 1 > > > > I am wondering if you are dealing with factors and have not looked at > your "list" with str(). Haven't tried my method above to see what would > happen in tat instance. > > > > > > > >> > >> Thanks, > >> Greg > >> [[alternative HTML version deleted]] > >> > >> ______________________________________________ > >> R-help@r-project.org mailing list > >> https://stat.ethz.ch/mailman/listinfo/r-help > >> PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > >> and provide commented, minimal, self-contained, reproducible code. > > > > David Winsemius, MD > > West Hartford, CT > > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
