I believe what I'm doing, is an ancova, because I have two categorical and a numerical explanatory variables, and a numerical response variable (this is the same experiment as before, the bacteria), and I'm just, at the minute (because I'm only half way through), doing some modelling and seeing what I get with what I currently have. And I'm paying attention to 95% CI for the different terms of a model, as well as the coefficient, and the explanatory power of the term and likelyhood that the same result could be obtained at random through the P values, derived from F. To be honest I havent checked much what my data distributions are like and such becasue I'm not finished collecting it yet. I mainly mentioned the ranking because it was given considerable mention in one of my texts sections on hypothesis testing on models.

On 07/01/2011 18:34, Greg Snow wrote:
A lot of this depends on what question you are really trying to answer.  For 
one way anova replacing y-values with their ranks essentially transforms the 
distribution to uniform (under the null) and the Central Limit Theorem kicks in 
for the uniform with samples larger than about 5, so the normal approximations 
are pretty good and the theory works, but what are you actually testing?  The 
most meaningful null that is being tested is that all data come from the exact 
same distribution.  So what does it mean when you reject that null?  It means 
that all the groups are not representing the same distribution, but is that 
because the means differ? Or the variances? Or the shapes? It can be any of 
those.  Some point out that if you make certain assumptions such as symmetry or 
shifts of the same distributions, then you can talk about differences in means 
or medians, but usually if I am using non-parametrics it is because I don't 
believe that things are symmetric and the shift idea doesn't fit in my mind.

Some alternatives include bootstrapping or permutation tests, or just 
transforming the data to get something closer to normal.

Now what does replacing by ranks do in 2-way anova where we want to test the 
difference in one factor without making assumptions about whether the other 
factor has an effect or not?  I'm not sure on this one.

I have seen regression on ranks, it basically tests for some level of 
relationship, but regression is usually used for some type of prediction and 
predicting from a rank-rank regression does not seem meaningful to me.

Fitting the regression model does not require normality, it is the tests on the 
coefficients and confidence and prediction intervals that assume normality 
(again the CLT helps for large samples (but not for prediction intervals)).  
Bootstrapping is an option for regression without assuming normality, 
transformations can also help.

--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Ben Ward
Sent: Thursday, January 06, 2011 2:00 PM
To: r-help@r-project.org
Subject: Re: [R] Assumptions for ANOVA: the right way to check the
normality

On 06/01/2011 20:29, Greg Snow wrote:
Some would argue to always use the kruskal wallis test since we never
know for sure if we have normality.  Personally I am not sure that I
understand what exactly that test is really testing.  Plus in your case
you are doing a two-way anova and kruskal.test does one-way, so it will
not work for your case.  There are other non-parametric options.
Just read this and had queries of my own and comments on this subject:
Would one of these options be to rank the data before doing whatever
model or test you want to do? As I understand it makes the place of the
data the same, but pulls extreme cases closer to the rest. Not an
expert
though.
I've been doing lm() for my work, and I don't know if that makes an
assumption of normality (may data is not normal). And I'm unsure of any
other assumptions as my texts don't really discuss them. Although I can
comfortably evaluate a model say using residual vs fitted, and F values
turned to P, resampling and confidence intervals, and looking at sums
of
squares terms add to explanation of the model. I've tried the plot()
function to help graphically evaluate a model, and I want to make sure
I
understand what it's showing me. I think the first, is showing me the
models fitted values vs the residuals, and ideally, I think the closer
the points are to the red line the better. The next plot is a Q-Q plot,
the closer the points to the line, the more normal the model
coefficients (or perhaps the data). I'm not sure what the next two
plots
are, but it is titled Scale-Location. And it looks to have the square
root of standardized residuals on y, and fitted model values on x.
Might
this be similar to the first plot? The final one is titled Residuals vs
Leverage, which has standardized residuals on y and leverage on x, and
something called Cooks Distance is plotted as well.

Thanks,
Ben. W
Whether to use anova and other normality based tests is really a
matter of what assumptions you are willing to live with and what level
of "close enough" you are comfortable with.  Consulting with a local
consultant with experience in these areas is useful if you don't have
enough experience to decide what you are comfortable with.
For your description, I would try the proportional odds logistic
regression, but again, you should probably consult with someone who has
experience rather than trying that on your own until you have more
training and experience.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111

From: Frodo Jedi [mailto:frodo.j...@yahoo.com]
Sent: Thursday, January 06, 2011 12:57 PM
To: Greg Snow; r-help@r-project.org
Subject: Re: [R] Assumptions for ANOVA: the right way to check the
normality

Ok,
I see ;-)

Let´s put in this way then. When do I have to use the kruskal wallis
test? I mean, when I am very sure that I have
to use it instead of ANOVA?

Thanks


Best regards

P.S.  In addition, which is the non parametric methods corresponding
to a 2 ways anova?..or have I to
repeat many times the kruskal wallis test?
________________________________
From: Greg Snow<greg.s...@imail.org>
To: Frodo Jedi<frodo.j...@yahoo.com>; Robert Baer<rb...@atsu.edu>;
"r-help@r-project.org"<r-help@r-project.org>
Sent: Thu, January 6, 2011 7:07:17 PM
Subject: RE: [R] Assumptions for ANOVA: the right way to check the
normality
Remember that an non-significant result (especially one that is still
near alpha like yours) does not give evidence that the null is true.
The reason that the 1st 2 tests below don't show significance is more
due to lack of power than some of the residuals being normal.  The only
test that I would trust for this is SnowsPenultimateNormalityTest
(TeachingDemos package, the help page is more useful than the function
itself).
But I think that you are mixing up 2 different concepts (a very
common misunderstanding).  What is important if we want to do normal
theory inference is that the coefficients/effects/estimates are
normally distributed.  Now since these coefficients can be shown to be
linear combinations of the error terms, if the errors are iid normal
then the coefficients are also normally distributed.  So many people
want to show that the residuals come from a perfectly normal
distribution.  But it is the theoretical errors, not the observed
residuals that are important (the observed residuals are not iid).  You
need to think about the source of your data to see if this is a
reasonable assumption.  Now I cannot fathom any universe (theoretical
or real) in which normally distributed errors added to means that they
are independent of will result in a finite set of integers, so an
assumption of exact normality is not reasonable (some may want to argue
this, but convincing me will be very difficult).  But looking for exact
normality is a bit of a red herring because, we also have the Central
Limit Theorem that says that if the errors are not normal (but still
iid) then the distribution of the coefficients will approach normality
as the sample size increases.  This is what make statistics doable
(because no real dataset entered into the computer is exactly normal).
The more important question is are the residuals "normal enough"?  for
which there is not a definitive test (experience and plots help).
But this all depends on another assumption that I don't think that
you have even considered.  Yes we can use normal theory even when the
random part of the data is not normally distributed, but this still
assumes that the data is at least interval data, i.e. that we firmly
believe that the difference between a response of 1 and a response of 2
is exactly the same as a difference between a 6 and a 7 and that the
difference from 4 to 6 is exactly twice that of 1 vs. 2.  From your
data and other descriptions, I don't think that that is a reasonable
assumption.  If you are not willing to make that assumption (like me)
then means and normal theory tests are meaningless and you should use
other approaches.  One possibility is to use non-parametric methods
(which I believe Frank has already suggested you use), another is to
use proportional odds logistic regression.


--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org<mailto:greg.s...@imail.org>
801.408.8111


-----Original Message-----
From: r-help-boun...@r-project.org<mailto:r-help-boun...@r-
project.org>   [mailto:r-help-boun...@r-
project.org<http://project.org>] On Behalf Of Frodo Jedi
Sent: Wednesday, January 05, 2011 3:22 PM
To: Robert Baer; r-help@r-project.org<mailto:r-help@r-project.org>
Subject: Re: [R] Assumptions for ANOVA: the right way to check the
normality

Dear Robert,
thanks so much!!!  Now I understand!
So you also think that I have to check only the residuals and not
the
data
directly.
Now just for curiosity I did the the shapiro test on the residuals.
The
problem
is that on fit3 I don´t get from the test
that the data are normally distribuited. Why? Here the data:

shapiro.test(residuals(fit1))
     Shapiro-Wilk normality test

data:  residuals(fit1)
W = 0.9848, p-value = 0.05693

#Here the test is ok: the test says that the data are distributed
normally
(p-value greather than 0.05)



shapiro.test(residuals(fit2))
     Shapiro-Wilk normality test

data:  residuals(fit2)
W = 0.9853, p-value = 0.06525

#Here the test is ok: the test says that the data are distributed
normally
(p-value greather than 0.05)



shapiro.test(residuals(fit3))
     Shapiro-Wilk normality test

data:  residuals(fit3)
W = 0.9621, p-value = 0.0001206



Now the test reveals p-value lower than 0.05: so the residuals for
fit3
are not
distributed normally....
Why I get this beheaviour? Indeed in the histogram and Q-Q plot for
fit3
residuals I get a normal distribution.
















________________________________
From: Robert Baer<rb...@atsu.edu<mailto:rb...@atsu.edu>>

Sent: Wed, January 5, 2011 8:56:50 PM
Subject: Re: [R] Assumptions for ANOVA: the right way to check the
normality

Someone suggested me that I don´t have to check the normality of
the
data, but
the normality of the residuals I get after the fitting of the
linear
model.
I really ask you to help me to understand this point as I don´t
find
enough
material online where to solve it.
Try the following:
# using your scrd data and your proposed models
fit1<- lm(response ~ stimulus + condition + stimulus:condition,
data=scrd)
fit2<- lm(response ~ stimulus + condition, data=scrd)
fit3<- lm(response ~ condition, data=scrd)

# Set up for 6 plots on 1 panel
op = par(mfrow=c(2,3))

# residuals function extracts residuals
# Visual inspection is a good start for checking normality
# You get a much better feel than from some "magic number" statistic
hist(residuals(fit1))
hist(residuals(fit2))
hist(residuals(fit3))

# especially qqnorm() plots which are linear for normal data
qqnorm(residuals(fit1))
qqnorm(residuals(fit2))
qqnorm(residuals(fit3))

# Restore plot parameters
par(op)

If the data are not normally distributed I have to use the kruskal
wallys test
and not the ANOVA...so please help
me to understand.
Indeed - Kruskal-Wallis is a good test to use for one factor data
that
is
ordinal so it is a good alternative to your fit3.
Your "response" seems to be a discrete variable rather than a
continuous
variable.
You must decide if it is reasonable to approximate it with a normal
distribution
which is by definition continuous.

I make a numerical example, could you please tell me if the data in
this table
are normally distributed or not?

Help!


number                  stimulus condition response
1            flat_550_W_realism        A        3
2            flat_550_W_realism        A        3
3            flat_550_W_realism        A        5
4            flat_550_W_realism        A        3
5            flat_550_W_realism        A        3
6            flat_550_W_realism        A        3
7            flat_550_W_realism        A        3
8            flat_550_W_realism        A        5
9            flat_550_W_realism        A        3
10            flat_550_W_realism        A        3
11            flat_550_W_realism        A        5
12            flat_550_W_realism        A        7
13            flat_550_W_realism        A        5
14            flat_550_W_realism        A        2
15            flat_550_W_realism        A        3
16            flat_550_W_realism        AH        7
17            flat_550_W_realism        AH        4
18            flat_550_W_realism        AH        5
19            flat_550_W_realism        AH        3
20            flat_550_W_realism        AH        6
21            flat_550_W_realism        AH        5
22            flat_550_W_realism        AH        3
23            flat_550_W_realism        AH        5
24            flat_550_W_realism        AH        5
25            flat_550_W_realism        AH        7
26            flat_550_W_realism        AH        2
27            flat_550_W_realism        AH        7
28            flat_550_W_realism        AH        5
29            flat_550_W_realism        AH        5
30        bump_2_step_W_realism        A        1
31        bump_2_step_W_realism        A        3
32        bump_2_step_W_realism        A        5
33        bump_2_step_W_realism        A        1
34        bump_2_step_W_realism        A        3
35        bump_2_step_W_realism        A        2
36        bump_2_step_W_realism        A        5
37        bump_2_step_W_realism        A        4
38        bump_2_step_W_realism        A        4
39        bump_2_step_W_realism        A        4
40        bump_2_step_W_realism        A        4
41        bump_2_step_W_realism        AH        3
42        bump_2_step_W_realism        AH        5
43        bump_2_step_W_realism        AH        1
44        bump_2_step_W_realism        AH        5
45        bump_2_step_W_realism        AH        4
46        bump_2_step_W_realism        AH        4
47        bump_2_step_W_realism        AH        5
48        bump_2_step_W_realism        AH        4
49        bump_2_step_W_realism        AH        3
50        bump_2_step_W_realism        AH        4
51        bump_2_step_W_realism        AH        5
52        bump_2_step_W_realism        AH        4
53        hole_2_step_W_realism        A        3
54        hole_2_step_W_realism        A        3
55        hole_2_step_W_realism        A        4
56        hole_2_step_W_realism        A        1
57        hole_2_step_W_realism        A        4
58        hole_2_step_W_realism        A        3
59        hole_2_step_W_realism        A        5
60        hole_2_step_W_realism        A        4
61        hole_2_step_W_realism        A        3
62        hole_2_step_W_realism        A        4
63        hole_2_step_W_realism        A        7
64        hole_2_step_W_realism        A        5
65        hole_2_step_W_realism        A        1
66        hole_2_step_W_realism        A        4
67        hole_2_step_W_realism        AH        7
68        hole_2_step_W_realism        AH        5
69        hole_2_step_W_realism        AH        5
70        hole_2_step_W_realism        AH        1
71        hole_2_step_W_realism        AH        5
72        hole_2_step_W_realism        AH        5
73        hole_2_step_W_realism        AH        5
74        hole_2_step_W_realism        AH        2
75        hole_2_step_W_realism        AH        6
76        hole_2_step_W_realism        AH        5
77        hole_2_step_W_realism        AH        5
78        hole_2_step_W_realism        AH        6
79    bump_2_heel_toe_W_realism        A        3
80    bump_2_heel_toe_W_realism        A        3
81    bump_2_heel_toe_W_realism        A        3
82    bump_2_heel_toe_W_realism        A        2
83    bump_2_heel_toe_W_realism        A        3
84    bump_2_heel_toe_W_realism        A        3
85    bump_2_heel_toe_W_realism        A        4
86    bump_2_heel_toe_W_realism        A        3
87    bump_2_heel_toe_W_realism        A        4
88    bump_2_heel_toe_W_realism        A        4
89    bump_2_heel_toe_W_realism        A        6
90    bump_2_heel_toe_W_realism        A        5
91    bump_2_heel_toe_W_realism        A        4
92    bump_2_heel_toe_W_realism        AH        7
93    bump_2_heel_toe_W_realism        AH        3
94    bump_2_heel_toe_W_realism        AH        4
95    bump_2_heel_toe_W_realism        AH        2
96    bump_2_heel_toe_W_realism        AH        5
97    bump_2_heel_toe_W_realism        AH        6
98    bump_2_heel_toe_W_realism        AH        4
99    bump_2_heel_toe_W_realism        AH        4
100    bump_2_heel_toe_W_realism        AH        4
101    bump_2_heel_toe_W_realism        AH        5
102    bump_2_heel_toe_W_realism        AH        2
103    bump_2_heel_toe_W_realism        AH        6
104    bump_2_heel_toe_W_realism        AH        5
105    hole_2_heel_toe_W_realism        A        3
106    hole_2_heel_toe_W_realism        A        3
107    hole_2_heel_toe_W_realism        A        1
108    hole_2_heel_toe_W_realism        A        3
109    hole_2_heel_toe_W_realism        A        3
110    hole_2_heel_toe_W_realism        A        5
111    hole_2_heel_toe_W_realism        A        2
112    hole_2_heel_toe_W_realism        AH        5
113    hole_2_heel_toe_W_realism        AH        1
114    hole_2_heel_toe_W_realism        AH        3
115    hole_2_heel_toe_W_realism        AH        6
116    hole_2_heel_toe_W_realism        AH        5
117    hole_2_heel_toe_W_realism        AH        4
118    hole_2_heel_toe_W_realism        AH        4
119    hole_2_heel_toe_W_realism        AH        3
120    hole_2_heel_toe_W_realism        AH        3
121    hole_2_heel_toe_W_realism        AH        1
122    hole_2_heel_toe_W_realism        AH        5
123 bump_2_combination_W_realism        A        4
124 bump_2_combination_W_realism        A        2
125 bump_2_combination_W_realism        A        4
126 bump_2_combination_W_realism        A        1
127 bump_2_combination_W_realism        A        4
128 bump_2_combination_W_realism        A        4
129 bump_2_combination_W_realism        A        2
130 bump_2_combination_W_realism        A        4
131 bump_2_combination_W_realism        A        2
132 bump_2_combination_W_realism        A        4
133 bump_2_combination_W_realism        A        2
134 bump_2_combination_W_realism        A        6
135 bump_2_combination_W_realism        AH        7
136 bump_2_combination_W_realism        AH        3
137 bump_2_combination_W_realism        AH        4
138 bump_2_combination_W_realism        AH        1
139 bump_2_combination_W_realism        AH        6
140 bump_2_combination_W_realism        AH        5
141 bump_2_combination_W_realism        AH        5
142 bump_2_combination_W_realism        AH        6
143 bump_2_combination_W_realism        AH        5
144 bump_2_combination_W_realism        AH        4
145 bump_2_combination_W_realism        AH        2
146 bump_2_combination_W_realism        AH        4
147 bump_2_combination_W_realism        AH        2
148 bump_2_combination_W_realism        AH        5
149 hole_2_combination_W_realism        A        5
150 hole_2_combination_W_realism        A        2
151 hole_2_combination_W_realism        A        4
152 hole_2_combination_W_realism        A        1
153 hole_2_combination_W_realism        A        5
154 hole_2_combination_W_realism        A        4
155 hole_2_combination_W_realism        A        3
156 hole_2_combination_W_realism        A        5
157 hole_2_combination_W_realism        A        2
158 hole_2_combination_W_realism        A        5
159 hole_2_combination_W_realism        A        5
160 hole_2_combination_W_realism        A        1
161 hole_2_combination_W_realism        AH        7
162 hole_2_combination_W_realism        AH        5
163 hole_2_combination_W_realism        AH        3
164 hole_2_combination_W_realism        AH        1
165 hole_2_combination_W_realism        AH        6
166 hole_2_combination_W_realism        AH        4
167 hole_2_combination_W_realism        AH        7
168 hole_2_combination_W_realism        AH        5
169 hole_2_combination_W_realism        AH        5
170 hole_2_combination_W_realism        AH        2
171 hole_2_combination_W_realism        AH        6
172 hole_2_combination_W_realism        AH        2
173 hole_2_combination_W_realism        AH        4




Thanks in advance



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