On Jan 16, 2011, at 4:17 PM, David Winsemius wrote:
On Jan 16, 2011, at 4:08 PM, Erin Hodgess wrote:
Dear R People:
I have the following:
ls(pattern="NY*")
[1] "CRAN_df" "CRAN_df0" "CRAN_df1" "CRAN_mat"
"CRAN_sp"
[6] "CRAN_spdf1" "CRAN_spdf2" "CRAN_spdf4" "delauney_NY"
"dist2_NY"
[11] "dist3_NY" "Gabriel_NY" "NY8a_nb" "rel_neigh_NY"
"scot_BNG"
[16] "SOI_NY"
rm(pattern="NY*")
Warning message:
In rm(pattern = "NY*") : object 'NY*' not found
How do I remove all of NY* items, please? I suspect it might be an
sapply issue
thanks,
Perhaps:
OOPs, missing paren:
rm(list= ls()[grep("NY", ls() )] )
If there is a pattern argument to rm (I haven't looked) then it's
possible that it would have succeeded with pattern="NY", assuming
you want any object name with "NY" someplace in it. The "*" looks
wrong for grepping. ".+" would have looked more greppish, but its
not really needed.
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodg...@gmail.com
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David Winsemius, MD
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
