Sandra,
Please provide a small, reproducible example of this issue.
You probably want to use ?is.nan and not the inequality
operator.
Similar example, contrast:
x <- NA
is.na(x)
x == NA
Sandra Stankowski wrote:
Hey there,
I tried to count the number of rows, where my data isn't NaN in a
certain column.
this was my guess:
(given is a data frame with 2069 rows and 17 cols)
NROW(data[jan,16] != NaN)
("jan" is defined this way: jan <- which(data[,2]==1, arr.ind= TRUE))
but I only get the number of columns where my data is "1" in the second
col. R isn't removing the NaN.
na.rm isn't working here.
I would appreciate your help.
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
