On Aug 18, 2011, at 5:43 PM, 1Rnwb wrote:
I have a data frame like this
xx<-
data
.frame
(cbind
(Sample
=c('Ctrl_6h','1+0_6h','1+200_6h','1+5k_6h','Ctrl_5K_6h','ConA_6h'),
IFIT1=c(24,25,24.7,24.5,24.2,24.8)))
grep('[[:digit:]]h',xx$Sample)
yy<-xx$Sample
strsplit(yy,"_")
You are getting tangled up because of stringsAsFactor + TRUE by
default. (The cbind is not needed and may have been confusing things
as well.)
xx <-
data
.frame
(Sample
=c('Ctrl_6h','1+0_6h','1+200_6h','1+5k_6h','Ctrl_5K_6h','ConA_6h'),
IFIT1=c(24,25,24.7,24.5,24.2,24.8),
stringsAsFactors=FALSE)
sub('(^.+)([[:digit:]]h$)', "\\2", xx$Sample)
1] "6h" "6h" "6h" "6h" "6h" "6h"
yy<-xx$Sample
strsplit(yy,"_")
#--------------
[[1]]
[1] "Ctrl" "6h"
[[2]]
[1] "1+0" "6h"
[[3]]
[1] "1+200" "6h"
[[4]]
[1] "1+5k" "6h"
[[5]]
[1] "Ctrl" "5K" "6h"
[[6]]
[1] "ConA" "6h"
Try instead to use these results to guide you
I have to extract the time information separated by '_' in the
sample names,
i tried grep and strsplit, it looks that i am not providing some
information
correctly. I would appreciate if someone can point me to the correct
way.
Thanks
Sharad
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