Sorry for the noise. The code should have been sapply(with(xx, strsplit(as.character(Sample), "_")), "[", 2)
instead of what I sent previously. HTH, Jorge On Aug 18, 2011, at 7:30 PM, Jorge I Velez wrote: > Hi Sharad, > > Try > > xx$newSample <- sapply(with(xx, strsplit(as.character(Sample), "_")), "[", 1) > xx > > HTH, > Jorge > > > On Aug 18, 2011, at 5:43 PM, 1Rnwb wrote: > >> I have a data frame like this >> xx<-data.frame(cbind(Sample=c('Ctrl_6h','1+0_6h','1+200_6h','1+5k_6h','Ctrl_5K_6h','ConA_6h'), >> IFIT1=c(24,25,24.7,24.5,24.2,24.8))) >> >> grep('[[:digit:]]h',xx$Sample) >> >> yy<-xx$Sample >> >> strsplit(yy,"_") >> >> I have to extract the time information separated by '_' in the sample names, >> i tried grep and strsplit, it looks that i am not providing some information >> correctly. I would appreciate if someone can point me to the correct way. >> Thanks >> Sharad >> >> -- >> View this message in context: >> http://r.789695.n4.nabble.com/splitting-sample-names-tp3753712p3753712.html >> Sent from the R help mailing list archive at Nabble.com. >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.