Hallo Can anyone tell me the difference between
foo$a[2] <- 1 and foo[2,"a"] <- 1 ? I thought that both expressions are equivalent, but when I run the following example, there is obviously a difference. > foo <- data.frame(a=NA,b=NA) > foo a b 1 NA NA > foo$a[1] <- 1 > foo$b[1] <- 2 > foo$a[2] <- 1 Error in `$<-.data.frame`(`*tmp*`, "a", value = c(1, 1)) : replacement has 2 rows, data has 1 > foo[2,"a"] <- 1 > foo a b 1 1 2 2 1 NA Thanks, Rebecca Hiller -- ETH Zürich Rebecca Hiller Institute of Agricultural Sciences LFW A2 Universitätsstrasse 2 8092 Zürich SWITZERLAND rebecca.hil...@ipw.agrl.ethz.ch http://www.gl.ethz.ch/ +41 44 632 31 90 Telefon +41 44 632 11 53 Fax ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
