Dear list, Sorry, but I cannot get my head around how and I could pass arguments along to high-level functions. What I have is a function that would benefit from me using ddply from the plyr package. However, I cannot get the arguments passing part right.
So, this is my function: > suspicious.vowels <- function(data,factors,f1,f2,evaluate.original.params=TRUE) { datOrig <- ddply(.data=data, .variables=as.quoted(factors), .fun=summarize, norm=vector.space(f1,f2)[["Vector norms"]] ) print(datOrig) } Of course, if I try to call this function, I get an error message telling me that the "f1" argument does not exist: > suspicious.vowels(pb,c("Type","Sex","Vowel"),"F1",F2) Error in mean(y, na.rm = na.rm) : object 'f1' not found However, the corresponding ddply call, when called from the console, does work: > head(ddply(pb,as.quoted(c("Type","Sex","Vowel")),summarize,norm=vector.space(F1,F2)[["Vector norms"]]),4) Type Sex Vowel norm 1 c f aa 250.1570 2 c f aa 497.2711 3 c f aa 172.3108 4 c f aa 109.4464 ... So, how do I modify the function to pass the arguments that I supply correctly? I cannot get my head around this enough to find the correct combination of deparse /substitute /... to get this right. I would be thankful for all the help I could get on this. /Fredrik -- "Life is like a trumpet - if you don't put anything into it, you don't get anything out of it." [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.