> Think you're going to have to explicitly define "hand tailor." I
> haven't a clue what you mean. (Someone else might of course).
Ah, I want to set a specific coefficient value for each of the terms
rather than rely on training. Thus given:
y ~ x0 + x1 + x2 + a
I would like to set:
a = 10
b0 = 20
b2 = 90,
etc.
I'm trying out my own training model and I would like to use the machinery
of the lm for evaluation and reporting but I would like to fix the beta
coefficients and other trained values independently of least-squares
regression.
Collin.
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