On Nov 12, 2013, at 11:59, <coll...@pitt.edu> wrote:
>> Think you're going to have to explicitly define "hand tailor." I >> haven't a clue what you mean. (Someone else might of course). > > Ah, I want to set a specific coefficient value for each of the terms > rather than rely on training. Thus given: > > y ~ x0 + x1 + x2 + a > > I would like to set: > > a = 10 > b0 = 20 > b2 = 90, > etc. > > I'm trying out my own training model and I would like to use the machinery > of the lm for evaluation and reporting but I would like to fix the beta > coefficients and other trained values independently of least-squares > regression. > I'm quite confused: if you set all the coefficients in advance, in what sense are you doing a linear regression? Even if this is possible, won't all the other estimates (i.e., standard error of betas) produced be junk since they aren't derived from the associated estimators? Michael > Collin. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.