Hi Veepsirtt, May be this helps: dat1 <- structure(list(V2 = c(11109.75, 11135.15, 11105.85, 11099.75, 11055.55, 11063.45, 11045.65, 11065, 11061.2, 11070.25, 11069.3, 11076, 11081.85, 11086.4, 11086.7, 11065.6, 11071.25, 11073.15, 11077.8, 11067.7, 11061.1, 11065.9, 11069.1, 11063.3, 11070.45, 11074.4, 11069.4, 11063.65, 11067.05, 11070.1, 11074, 11069.6, 11072.65, 11073.7, 11061.35, 11064.2, 11066.85, 11078.15, 11079.65, 11079.5, 11075.9, 11066.95, 11072.55, 11068.85, 11073.5, 11067.6, 11055.3, 11053.3, 11052.65, 11047.6, 11045.25, 11028.9, 11036.15, 11034.3, 11044.05, 11030.65, 11036.6, 11039.75, 11035.35, 11019.05 )), .Names = "V2", class = "data.frame", row.names = c(NA, 60L )) dat1[seq(5,nrow(dat1),by=5),,drop=FALSE] #or dat1[((seq(nrow(dat1))-1)%%5+1)==5,,drop=FALSE]
A.K. On Sunday, January 19, 2014 9:40 AM, "veepsi...@gmail.com" <veepsi...@gmail.com> wrote: Hi A.K sir 1,11109.75 2,11135.15 3,11105.85 4,11099.75 5,11055.55 6,11063.45 7,11045.65 8,11065 9,11061.2 10,11070.25 11,11069.3 12,11076 13,11081.85 14,11086.4 15,11086.7 16,11065.6 17,11071.25 18,11073.15 19,11077.8 20,11067.7 21,11061.1 22,11065.9 23,11069.1 24,11063.3 25,11070.45 26,11074.4 27,11069.4 28,11063.65 29,11067.05 30,11070.1 31,11074 32,11069.6 33,11072.65 34,11073.7 35,11061.35 36,11064.2 37,11066.85 38,11078.15 39,11079.65 40,11079.5 41,11075.9 42,11066.95 43,11072.55 44,11068.85 45,11073.5 46,11067.6 47,11055.3 48,11053.3 49,11052.65 50,11047.6 51,11045.25 52,11028.9 53,11036.15 54,11034.3 55,11044.05 56,11030.65 57,11036.6 58,11039.75 59,11035.35 60,11019.05 thanks veepsirtt _____________________________________ Sent from http://r.789695.n4.nabble.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
