HI, I am not sure this is what you meant. a <- read.table(text="1 2 3 4 5 6 1 Mal 1 Layer 22 M 100000 2 Mahesh 2 Actor 45 M 150000000 3 Tarak 3 Actor 30 M 150000000 4 Pawan 4 Actor 47 M 150000000 5 Charan 5 Actor 32 M 100000000 6 Prabhas 6 Actor 32 M 100000000 7 Arjun 7 Actor 31 M 90000000 8 Naresh 8 Actor 29 M 30000000 9 Nithin 9 Actor 30 M 30000000 10 Puri 10 Director 38 M 100000000",sep="",header=TRUE,check.names=FALSE,stringsAsFactors=FALSE)
res1 <- setNames(as.data.frame(table(cut(a[,4],breaks=seq(0,100,by=20),labels=c("0-20","20-40","40-60","60-80","80-100")))),c("Bins","count")) #or res2 <- setNames(as.data.frame(table(cut(a$`4`,breaks=seq(0,100,by=20),labels=c("0-20","20-40","40-60","60-80","80-100")))),c("Bins","count")) identical(res1,res2) #[1] TRUE #or change the colnames and apply your code colnames(a)[4] <- "AGE" A.K. On Thursday, February 6, 2014 3:47 AM, Malyadri Putchakayala <malyadri.putchakay...@nuevora.com> wrote: 1 2 3 4 5 6 1 Mal 1 Layer 22 M 100000 2 Mahesh 2 Actor 45 M 150000000 3 Tarak 3 Actor 30 M 150000000 4 Pawan 4 Actor 47 M 150000000 5 Charan 5 Actor 32 M 100000000 6 Prabhas 6 Actor 32 M 100000000 7 Arjun 7 Actor 31 M 90000000 8 Naresh 8 Actor 29 M 30000000 9 Nithin 9 Actor 30 M 30000000 10 Puri 10 Director 38 M 100000000 a<-read.csv("X:T11.csv",stringsAsFactors=F) Bins<-as.data.frame(table(cut(a$AGE,breaks=seq(0,100,by=20), labels=c("0-20","20-40","40-60","60-80","80-100")))) colnames(Bins) <- c("Bins", "count") Bins HI, Above code I am Using with Which one Integer then I am Binning a$AGE. Now , My dataset Not Mention Variable Names Then How to Find Binning.(How bin above dataset ) ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.