Hi,
My solution was based on the input dataset you showed. If xy@12_g.com is
"xy1...@gmail.com" (or both of them exist in the dataset?? Not clear!)., then
try:
dat <- read.table(text="Emails
mal...@gmail.com
mah...@gmail.com
x...@gmail.com
ravi_...@yahoo.com
lavk....@rediff.com
xy1...@gmail.com",sep="",header=TRUE,stringsAsFactors=FALSE)
library(stringr)
vec1 <- dat$Emails
vec2 <-
gsub("\\.[[:alnum:]]+$","",gsub("^([[:alpha:]]+)(\\d+.*)","\\1_\\2",vec1))
indx <- which(str_count(vec2,"\\_")>1)
vec2[indx] <- str_replace(vec2[indx],"_","*")
indx1 <- setdiff(grep("[[:punct:]]+",gsub("\\@.*","",vec2)),indx)
res <- setNames(cbind(dat,do.call(rbind,lapply(seq_along(vec2),function(i) if(i
%in% indx1){strsplit(vec2[i],"[_@.]")[[1]]} else if(i %in%
indx){strsplit(vec2[i],"[*@]")[[1]]} else
strsplit(gsub("(.*)(\\@.*)","\\1*\\2",vec2[i]),"[*@]")[[1]]))),c("Emails","f.name","l.name","domain"))
res[sapply(res,is.factor)] <- lapply(res[sapply(res,is.factor)],as.character)
res
A.K.
On Tuesday, February 11, 2014 5:31 AM, Malyadri Putchakayala
<malyadri.putchakay...@nuevora.com> wrote:
HI,
Emails f.name l.name domain
#1 mal...@gmail.com Mal 123 Gmail
#2 mah...@gmail.com Mahi r Gmail
#3 x...@gmail.com xyz Gmail
#4 ravi_...@yahoo.com Ravi 123 yahoo
#5 lavk....@rediff.com Lavk lll rediff
#6 xy@12_g.com xy 12_g
ABOVE IS ALL ARE RIGHT.BUT MY REQUIREMENT IS 12_G IS ALSO LAST NAME
Emails f.name l.name domain
#1 mal...@gmail.com Mal 123 Gmail
#2 mah...@gmail.com Mahi r Gmail
#3 x...@gmail.com xyz Gmail
#4 ravi_...@yahoo.com Ravi 123 yahoo
#5 lavk....@rediff.com Lavk lll rediff
#6 xy1...@gmail.com xy 12_g Gmail
MY FINAL OUTPUT IS THIS TYPE.IF POSSIBLE PLEASE HELP
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