On Wed, Jun 04, 2008 at 07:36:04PM -0600, Manli Yan wrote: > no,the id is variable of a table,such as: > treatment id age response > low 1 50 20 > low 1 60 30 > high 5 50 30 > high 5 60 40 > > ....... > > I want to rearranage the table according the id (increasing)
Ah - that's a different story. To sort your data frame by id: foo <- foo[order(foo$id), ] > ,since id is not strictly from 1~n,it is in increasing order but > sometime jump through many number like 1 1 5 5,I like them to be 1 1 2 > 2~ foo$id <- as.integer(factor(foo$id)) seems to do what wou want, except I am not sure if factor is guaranteed to encode the values in ascending order. If it isn't this is a bad idea. Alternatively, this should work: foo$id <- cumsum(as.logical(diff(foo$id))) + 1 I'm sure there is a more elegant way but can't think of one right now. cu Philipp -- Dr. Philipp Pagel Lehrstuhl für Genomorientierte Bioinformatik Technische Universität München Wissenschaftszentrum Weihenstephan 85350 Freising, Germany http://mips.gsf.de/staff/pagel ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.