Hi Bill, One quick question. What if I wanted to use curve() for a uniform distribution?
Say, unif(0.5, 1.3), 0 elsewhere. My R code: func <- function(min, max){ 1 / (max - min) } curve(func(min = 0.5, max = 1.3), from = 0, to = 2) curve() wants an expression, but I have a constant. And I want zero everywhere else. Thanks, Mike On Thu, Jan 29, 2015 at 10:34 PM, C W <tmrs...@gmail.com> wrote: > Hi Bill, > > You solved by problem. For some reason, I thought xname was only > referring to name of the x-axis. > > I remember last time I fixed it, it was something about xname, couldn't > get it right this time. > > Thanks! Saved me hours from frustration. > > Mike > > On Thu, Jan 29, 2015 at 9:04 PM, William Dunlap <wdun...@tibco.com> wrote: > >> Does >> help(curve) >> talk about its 'xname' argument? >> >> Try >> curve(10*foofoo, from=0, to=17, xname="foofoo") >> >> You will have to modify your function, since curve() will >> call it once with a long vector for the independent variable >> and func(rnorm(10), rnorm(10), mu=seq(0,5,len=501)) won't >> work right. >> >> >> Bill Dunlap >> TIBCO Software >> wdunlap tibco.com >> >> On Thu, Jan 29, 2015 at 5:43 PM, C W <tmrs...@gmail.com> wrote: >> >>> Hi Rui, >>> >>> Thank you for your help. That works for now, but eventually, I need to >>> be >>> pass in x and y. >>> >>> Is there a way to tell the curve() function, x is a fix vector, mu is a >>> variable! >>> >>> Thanks, >>> >>> Mike >>> >>> On Thu, Jan 29, 2015 at 5:25 PM, Rui Barradas <ruipbarra...@sapo.pt> >>> wrote: >>> >>> > Hello, >>> > >>> > The following will work, but I don't know if it's what you want. func2 >>> > will get x and y from the global environment. >>> > >>> > func2 <- function(mu){ >>> > x + y + mu ^ 2 >>> > } >>> > >>> > curve(func2, from = 0, to = 10) >>> > >>> > >>> > Hope this helps, >>> > >>> > Rui Barradas >>> > >>> > Em 29-01-2015 21:02, C W escreveu: >>> > >>> >> Hi all, >>> >> >>> >> I want to graph a curve as a function of mu, not x. >>> >> >>> >> Here's the R code: >>> >> >>> >> x <- rnorm(10) >>> >> y <- rnorm(10) >>> >> >>> >> func <- function(x, y, mu){ >>> >> x + y + mu ^ 2 >>> >> } >>> >> >>> >> curve(f = func(x = x, y = y, mu), from = 0, to = 10) >>> >> I know I can change variable mu to x, but is there a way to tell R >>> that mu >>> >> is the variable of interest, not x. >>> >> >>> >> Thanks in advance, >>> >> >>> >> Mike >>> >> >>> >> [[alternative HTML version deleted]] >>> >> >>> >> ______________________________________________ >>> >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >>> >> https://stat.ethz.ch/mailman/listinfo/r-help >>> >> PLEASE do read the posting guide http://www.R-project.org/ >>> >> posting-guide.html >>> >> and provide commented, minimal, self-contained, reproducible code. >>> >> >>> >> >>> >>> [[alternative HTML version deleted]] >>> >>> ______________________________________________ >>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >>> >> >> > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.