Maybe this was your solution?
blocC <- c(rep(x=c(1:13), times=84))
blocC <- arrange(.data = data.frame(blocC), blocC)
The second line sorts, but that may not be needed depending on application. The
object class is also different in the sorted solution.
Tim
-----Original Message-----
From: R-help <r-help-boun...@r-project.org> On Behalf Of Francesca PANCOTTO via
R-help
Sent: Thursday, June 13, 2024 2:22 PM
To: r-help@r-project.org
Subject: Re: [R] Create a numeric series in an efficient way
[External Email]
I apologize, I solved the problem, sorry for that.
f.
Il giorno gio 13 giu 2024 alle ore 16:42 Francesca PANCOTTO <
francesca.panco...@unimore.it> ha scritto:
> Dear Contributors
> I am trying to create a numeric series with repeated numbers, not
> difficult task, but I do not seem to find an efficient way.
>
> This is my solution
>
> blocB <- c(rep(x = 1, times = 84), rep(x = 2, times = 84), rep(x = 3,
> times = 84), rep(x = 4, times = 84), rep(x = 5, times = 84), rep(x =
> 6, times = 84), rep(x = 7, times = 84), rep(x = 8, times = 84), rep(x
> = 9, times = 84), rep(x = 10, times = 84), rep(x = 11, times = 84),
> rep(x = 12, times = 84), rep(x = 13, times = 84))
>
> which works but it is super silly and I need to create different
> variables similar to this, changing the value of the repetition, 84 in this
> case.
> Thanks for any help.
>
>
> F.
>
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