Hi there, Could anyone please help me to understand what should be done in order not to get this error message: Error: evaluation nested too deeply: infinite recursion / options(expressions=)?
Here is my code: determinant<- function(x){det(matrix(c(1.0,0.2,0.5,0.8,0.2,1.0,0.5,0.6,0.5,0.5,0.5,1.0,x,0.8,0.6,x,1.0),ncol=4,byrow=T))} matrix<- function(x){(matrix(c(1.0,0.2,0.5,0.8,0.2,1.0,0.5,0.6,0.5,0.5,0.5,1.0,x,0.8,0.6,x,1.0),ncol=4,byrow=T))} conditional<-function(x,varcov){ varcov<-matrix(x) sigmaxx<-varcov[3,3] sigmaxz<-varcov[3,1:2] sigmayy<-varcov[4,4] sigmayz<-varcov[4,1:2] sigmazx<-varcov[1:2,3] sigmazy<-varcov[1:2,4] sigmazz<-varcov[1:2,1:2] (x-sigmaxz%*%solve(sigmaZZ)%*%sigmazy)/sqrt((sigmaxx-sigmaxz%*%solve(sigmaZZ)%*%sigmazx)*(sigmayy-sigmayz%*%solve(sigmaZZ)%*%sigmazy))} interval<-uniroot(determinant,lower = min(c(0,1)), upper = max(c(0,1))) I tried also with the code below, but got the same Error message. lower.bound<-uniroot(determinant,c(0,0.5))$root upper.bound<-uniroot(determinant,c(0.51,1))$root Your help will be greatly appreciate! Ana [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.