Hi Folks, I'm wondering if there's a compact way to achieve the following. The "dream" is that, by analogy with
rep(c(0,1),times=c(3,4)) # [1] 0 0 0 1 1 1 1 one could write rep(c(0,1),times=c(3,4,5,6)) which would produce # [1] 0 0 0 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1 in effect "recycling" x through 'times'. The objective is to produce a vector of alternating runs of 0s and 1s, with the lengths of the runs supplied as a vector. Indeed, more generally, something like rep(c(0,1,2), times=c(1,2,3,2,3,4)) # [1] 0 1 1 2 2 2 0 0 1 1 1 2 2 2 2 Suggestions appreciated! With thanks, Ted. -------------------------------------------------------------------- E-Mail: (Ted Harding) <[EMAIL PROTECTED]> Fax-to-email: +44 (0)870 094 0861 Date: 20-Oct-08 Time: 21:57:15 ------------------------------ XFMail ------------------------------ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
