On 20 Oct 2008, at 22:57, (Ted Harding) wrote:
I'm wondering if there's a compact way to achieve the following. The "dream" is that one could write rep(c(0,1),times=c(3,4,5,6)) which would produce # [1] 0 0 0 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1 in effect "recycling" x through 'times'.
rep2 <- function (x, times) rep(rep(x, length.out=length(times)), times) rep2(c(0,1),times=c(3,4,5,6)) [1] 0 0 0 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1 Any prizes for shortest solution? ;-) Best, Stefan ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
