Jorge Ivan Velez wrote: > >> B=0:12 >> B >> > [1] 0 1 2 3 4 5 6 7 8 9 10 11 12 > >> ifelse(B%in%c(0:9),'A','B') >> > [1] "A" "A" "A" "A" "A" "A" "A" "A" "A" "A" "B" "B" "B" > >
given the example, the solution would rather be if (B %in% as.character(0:9)) "A" else "B" or maybe if (as.numeric(B) %in% 0:9) "A" else "B" > >> On Wed, Nov 19, 2008 at 4:42 PM, CE.KA <[EMAIL PROTECTED]> wrote: >> >> >>> Hi R users, >>> >>> Is there a way to simplify this instruction: >>> ifelse(B=="0","A", >>> ifelse(B=="1","A", >>> ifelse(B=="2","A", >>> ifelse(B=="3","A", >>> ifelse(B=="4","A", >>> ifelse(B=="5","A", >>> ifelse(B=="6","A", >>> ifelse(B=="7","A", >>> ifelse(B=="8","A", >>> ifelse(B=="9","A","B")))))))))) >>> >>> i am looking for something like this: >>> >>> ifelse(B=="(0:9)","A","B") >>> >>> ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.