On Nov 19, 2008, at 8:38 PM, Wacek Kusnierczyk wrote:
Jorge Ivan Velez wrote:
B=0:12
B
[1] 0 1 2 3 4 5 6 7 8 9 10 11 12
ifelse(B%in%c(0:9),'A','B')
[1] "A" "A" "A" "A" "A" "A" "A" "A" "A" "A" "B" "B" "B"
given the example, the solution would rather be
if (B %in% as.character(0:9)) "A" else "B"
or maybe
if (as.numeric(B) %in% 0:9) "A" else "B"
Er, ... The solution offered by Velez duplicates the action of the
nested ifelse expressions offered by the original poster. Your
alternatives do not. The ifelse(cond, consequenceA, consequenceB)
function operates on a vector and returns a vector of equal length,
whereas:
if cond consequenceA else consequenceB # only returns a single
item.
> B <- 0:12
> ifelse(B %in% c(0:9), 'A', 'B')
[1] "A" "A" "A" "A" "A" "A" "A" "A" "A" "A" "B" "B" "B"
> if (B %in% as.character(0:9)) "A" else "B"
[1] "A"
Warning message:
In if (B %in% as.character(0:9)) "A" else "B" :
the condition has length > 1 and only the first element will be used
> if (as.numeric(B) %in% 0:9) "A" else "B"
[1] "A"
Warning message:
In if (as.numeric(B) %in% 0:9) "A" else "B" :
the condition has length > 1 and only the first element will be used
> ifelse(B=="0","A",
+ ifelse(B=="1","A",
+ ifelse(B=="2","A",
+ ifelse(B=="3","A",
+ ifelse(B=="4","A",
+ ifelse(B=="5","A",
+ ifelse(B=="6","A",
+ ifelse(B=="7","A",
+ ifelse(B=="8","A",
+ ifelse(B=="9","A","B"))))))))))
[1] "A" "A" "A" "A" "A" "A" "A" "A" "A" "A" "B" "B" "B"
>
--
David Winsemius
Heritage Labs
On Wed, Nov 19, 2008 at 4:42 PM, CE.KA <[EMAIL PROTECTED]> wrote:
Hi R users,
Is there a way to simplify this instruction:
ifelse(B=="0","A",
ifelse(B=="1","A",
ifelse(B=="2","A",
ifelse(B=="3","A",
ifelse(B=="4","A",
ifelse(B=="5","A",
ifelse(B=="6","A",
ifelse(B=="7","A",
ifelse(B=="8","A",
ifelse(B=="9","A","B"))))))))))
i am looking for something like this:
ifelse(B=="(0:9)","A","B")
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