You can use Mark's code by giving levels to the factor, e.g.
as.numeric(factor(unlist(strsplit("ABCDAXYZ", "")), levels=LETTERS))
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of [EMAIL PROTECTED]
Sent: Monday, November 24, 2008 9:15 AM
To: [EMAIL PROTECTED]
Cc: r-help@r-project.org
Subject: Re: [R] Calculating sum of letter values
Hi Mark
Thanks, that's almost exactly what I need...theres just a slight
difference with my requirement, in that I am looking for the actual
index value in the alphabetical sequence, so that instead of:
as.numeric(factor(unlist(strsplit("XYZ",""))))
[1] 1 2 3
I would expect to see
[1] 24 25 26
I have got it to work in a fairly non-elegant manner, using the
following code:
sum ( unlist(lapply(strsplit("TESTING",""), function(x) match(x,LETTERS)
)) )
And over a list of names, this becomes:
lapply(namelist, function(Z) { sum ( unlist(lapply(strsplit(Z,""),
function(x) match(x,LETTERS) )) ) } )
But this is kind of ugly....
Rory Winston
RBS Global Banking & Markets
Office: +44 20 7085 4476
-----Original Message-----
From: Marc Schwartz [mailto:[EMAIL PROTECTED]
Sent: 24 November 2008 15:09
To: WINSTON, Rory, GBM
Cc: r-help@r-project.org
Subject: Re: [R] Calculating sum of letter values
on 11/24/2008 08:57 AM [EMAIL PROTECTED] wrote:
> Hi all
>
> If I have a string, say "ABCDA", and I want to convert this to the sum
of the letter values, e.g.
>
> A -> 1
> B -> 2
>
> etc, so "ABCDA" = 1+2+3+4+1 = 11
>
> Is there an elegant way to do this? Trying something like
>
> which(LETTERS %in% unlist(strsplit("ABCDA", ""))) is not quite
> correct, as it does not count repeated characters. I guess what I need
is some kind of lookup table?
>
> Cheers
> Rory
> sum(as.numeric(factor(unlist(strsplit("ABCDA", "")))))
[1] 11
Convert the letters to factors, after splitting the vector, which then
enables the use of the underlying numeric codes:
> as.numeric(factor(unlist(strsplit("ABCDA", ""))))
[1] 1 2 3 4 1
HTH,
Marc Schwartz
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