> Thanks, that's almost exactly what I need...theres just a slight > difference with my requirement, in that I am looking for the actual > index value in the alphabetical sequence, so that instead of: > > as.numeric(factor(unlist(strsplit("XYZ","")))) > [1] 1 2 3 > > I would expect to see > > [1] 24 25 26
A minor modeification of Mark's solution works in this case: as.numeric(factor(unlist(strsplit("XYZ", "")), levels=LETTERS)) # [1] 24 25 26 Regards, Richie. Mathematical Sciences Unit HSL ------------------------------------------------------------------------ ATTENTION: This message contains privileged and confidential inform...{{dropped:20}} ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.