I seriously doubt that a survfit object could only contain that information. I suspect that you are erroneously thinking that what print.survfit offers is the entire story.

What does str(survfit(<formula>, data=<dataframe>) ) show you?

> data(aml)
> aml.mdl <- survfit(Surv(time, status) ~ x, data=aml)
# this is with survfit.Design since I load Hmisc/Design by default now.
> str(aml.mdl)
List of 18
 $ n            : int 23
 $ time         : num [1:20] 9 13 18 23 28 31 34 45 48 161 ...
 $ n.risk       : num [1:20] 11 10 8 7 6 5 4 3 2 1 ...
 $ n.event      : num [1:20] 1 1 1 1 0 1 1 0 1 0 ...
 $ surv         : num [1:20] 0.909 0.818 0.716 0.614 0.614 ...
 $ type         : chr "right"
 $ ntimes.strata: Named int [1:2] 10 10
  ..- attr(*, "names")= chr [1:2] "1" "2"
 $ strata       : Named num [1:2] 10 10
  ..- attr(*, "names")= chr [1:2] "Maintained" "Nonmaintained"
 $ strata.all   : Named int [1:2] 11 12
  ..- attr(*, "names")= chr [1:2] "Maintained" "Nonmaintained"
 $ std.err      : num [1:20] 0.0953 0.1421 0.1951 0.2487 0.2487 ...
 $ upper        : num [1:20] 0.987 0.951 0.899 0.835 0.835 ...
 $ lower        : num [1:20] 0.508 0.447 0.35 0.266 0.266 ...
 $ conf.type    : chr "log-log"
 $ conf.int     : num 0.95
 $ maxtime      : num 161
 $ units        : chr "Day"
 $ time.label   : chr "time"
$ call : language survfit(formula = Surv(time, status) ~ x, data = aml)
 - attr(*, "class")= chr "survfit"
>

I also don't think survfit returns a Cox model.


On Feb 17, 2009, at 10:37 AM, Bernhard Reinhardt wrote:

Hi!

I came across R just a few days ago since I was looking for a toolbox for cox-regression.

I´ve read
"Cox Proportional-Hazards Regression for Survival Data
Appendix to An R and S-PLUS Companion to Applied Regression" from John Fox.

As described therein plotting survival-functions works well (plot(survfit(model))). But I´d like to do some manipulation with the survival-functions before plotting them e.g. dividing one survival-function by another.

survfit() only returns an object of the following structure

    n events median 0.9LCL 0.9UCL
55.000 55.000  1.033  0.696  1.637

Can you tell me how I can calculate a survival- or baseline-function out of these values and how I extract the values from the object? I ´m sure the calculation is done by the corresponding plot-routine, but I couldn´t find that one either.

Regards

Bernhard

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to