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>=20 > library(abind) ## array binding I've looked into using abind()=2C but it seems I might not understand it pr= operly. I can build my 2 table array=2C and insert a row into each table using: =A0=A0=A0=A0=A0=A0=A0 x <- array(0=2Cc(1=2C3=2C2)) =A0=A0=A0=A0=A0=A0=A0 x[=2C=2C1] <- c(1=2C2=2C3) =A0=A0=A0=A0=A0=A0=A0 x[=2C=2C2] <- c(7=2C8=2C9) And I can use rbind() or abind() to add a row to the first table and assign= it to a separate object. =A0=A0=A0=A0=A0=A0=A0 y <- rbind(x[=2C=2C1]=2C c(4=2C5=2C6)) =A0=A0=A0=A0=A0=A0=A0 z <- abind(x[=2C=2C1]=2C c(4=2C5=2C6)=2Calong=3D0) But I can't determine how to add a row in place to a single table of the 3 = dimensional array. For example=2C this does not work: =A0=A0=A0=A0=A0=A0=A0 x[=2C=2C1] <- abind(x[=2C=2C1]=2C c(4=2C5=2C6)=2Calon= g=3D0) Error in x[=2C =2C 1] <- abind(x[=2C =2C 1]=2C c(4=2C 5=2C 6)=2C along =3D = 0) :=20 =A0 number of items to replace is not a multiple of replacement length I would like 'x' to be: > x =2C =2C 1 =A0=A0=A0=A0 [=2C1] [=2C2] [=2C3] [1=2C]=A0=A0=A0 1=A0=A0=A0 2=A0=A0=A0 3 [2=2C]=A0=A0=A0 4=A0=A0=A0 5=A0=A0=A0 6 =2C =2C 2 =A0=A0=A0=A0 [=2C1] [=2C2] [=2C3] [1=2C]=A0=A0=A0 7=A0=A0=A0 8=A0=A0=A0 9 Thanks for any help. =20 _________________________________________________________________ Hotmail: Trusted email with Microsoft=92s powerful SPAM protection. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.