Unfortunately, I can't read your examples. Can you repost without the
formatting characters which are confusing when rendered in plain text?
One thing to keep in mind is that a R array is a regular object -- e.g., if you have a 2
x 3 x 4 array, then if you want to add a row to a slice, you must add a row to all the
slices. When I read "to add a row in place to a single table of the 3 dimensional
array" it sounds like you might be trying to do something that's not possible with R
arrays. However, if I could see your examples, then I probably give more help.
-- Tony Plate
Another Oneforyou wrote:
<4adbca02.8020...@temple.edu>
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library(abind) ## array binding
I've looked into using abind()=2C but it seems I might not understand it pr=
operly.
I can build my 2 table array=2C and insert a row into each table using:
=A0=A0=A0=A0=A0=A0=A0 x <- array(0=2Cc(1=2C3=2C2))
=A0=A0=A0=A0=A0=A0=A0 x[=2C=2C1] <- c(1=2C2=2C3)
=A0=A0=A0=A0=A0=A0=A0 x[=2C=2C2] <- c(7=2C8=2C9)
And I can use rbind() or abind() to add a row to the first table and assign=
it to a separate object.
=A0=A0=A0=A0=A0=A0=A0 y <- rbind(x[=2C=2C1]=2C c(4=2C5=2C6))
=A0=A0=A0=A0=A0=A0=A0 z <- abind(x[=2C=2C1]=2C c(4=2C5=2C6)=2Calong=3D0)
But I can't determine how to add a row in place to a single table of the 3 =
dimensional array. For example=2C this does not work:
=A0=A0=A0=A0=A0=A0=A0 x[=2C=2C1] <- abind(x[=2C=2C1]=2C c(4=2C5=2C6)=2Calon=
g=3D0)
Error in x[=2C =2C 1] <- abind(x[=2C =2C 1]=2C c(4=2C 5=2C 6)=2C along =3D =
0) :=20
=A0 number of items to replace is not a multiple of replacement length
I would like 'x' to be:
x
=2C =2C 1
=A0=A0=A0=A0 [=2C1] [=2C2] [=2C3]
[1=2C]=A0=A0=A0 1=A0=A0=A0 2=A0=A0=A0 3
[2=2C]=A0=A0=A0 4=A0=A0=A0 5=A0=A0=A0 6
=2C =2C 2
=A0=A0=A0=A0 [=2C1] [=2C2] [=2C3]
[1=2C]=A0=A0=A0 7=A0=A0=A0 8=A0=A0=A0 9
Thanks for any help.
=20
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