Great. If you mean the crantastic r package, sorry I wasn't clear, I meant the crantastic website http://crantastic.org/. If you meant the description of plyr then if the description looks useful then click the link taking you to the package documentation and read it. Same for any of the other packages.
The idea, I think, is that its a good idea to make yourself aware of the most popular packages i.e. perhaps just read the descriptions of the top 30 or something like that maybe. Maybe it helps you avoid re-inventing the wheel. That seems to be the case here. Re Don's reply, sure you can use split(). But that will use more memory. And using paste for this? Ok, it works, but don't you want to use better ways? data.table should be much faster and more convenient, quicker to write than split and paste like that. HTH "Ivan Calandra" <ivan.calan...@uni-hamburg.de> wrote in message news:4b59bdc5.60...@uni-hamburg.de... I didn't know about crantastic actually. I've looked what it is exactly and it indeed looks interesting, but I don't really see how I would know that it would help me for the task. There's a description of what it was built for, but how can I then know which function from this package can help me? Thanks for your answer (you all), I'll work on it! I'll keep you informed if it doesn't work (!), and I'll go vote on crantastic when I'll have a bit more experience with the packages I use (right now I'm just using the ones I was told for one specific function), but don't worry I won't forget. As you said "It only works if users contribute to it". That makes the power of R! Ivan Le 1/21/2010 19:01, Matthew Dowle a écrit : > One way is : > > dataset = data.table(ssfamed) > dataset[,< whatever "some functions" are on Asfc, Smc, epLsar, etc>, > by="SPECSHOR,BONE"] > > Your SPECSHOR and BONE names will be in your result alongside the results > of > the<whatever ...> > > Or try package plyr which does this sort of thing too. And sqldf may be > better if you know SQL and prefer it. There are actually zillions of ways > to do it : by(), doBy() etc etc > > If you get your code working the way its constructed currently, its going > to be very slow, because of those "==". data.table doesn't do that and > is > pretty fast for this kind of thing. You might find that plyr is easier to > use and more flexible though if speed isn't an issue, depending on > exactly > what you want to do. > > Whichever way you decide, consider voting on crantastic for the package > you > end up using, and that may be a quick and easy way for you to help new R > users in the future, and help us all by reducing the r-help traffic on the > same subject over and over again. > > Note that plyr is the 2nd spot on crantastic, it would have solved your > problem without needing to write that code. If you check crantastic first > and make sure you're aware of popular packages, it might avoid getting > stuck > in this way again. It only works if users contribute to it though. > > > "Ivan Calandra"<ivan.calan...@uni-hamburg.de> wrote in message > news:4b587cdd.4070...@uni-hamburg.de... > >> Hi everybody! >> >> To use some functions, I have to transform my dataset into a list, where >> each element contains one group, and I have to prepare a list for each >> variable I have (altogether I have 15 variables, and many entries per >> factor level) >> >> Here is some part of my dataset: >> SPECSHOR BONE Asfc Smc epLsar >> cotau tx 454.390369 29.261638 0.001136 >> cotau tx 117.445711 4.291884 0.00056 >> cotau tx 381.024682 15.313017 0.002324 >> cotau tx 159.081789 18.134533 0.000462 >> cotau tm 160.641503 6.411332 0.000571 >> cotau tm 79.238023 3.828254 0.001182 >> cotau tm 143.20655 11.921899 0.000192 >> cotau tm 115.476996 33.116386 0.000417 >> cotau tm 594.256234 72.538131 0.000477 >> eqgre tx 188.261324 8.279096 0.000777 >> eqgre tx 152.444216 2.596325 0.001022 >> eqgre tx 256.601507 8.279096 0.000566 >> eqgre tx 250.816445 18.134533 0.000535 >> eqgre tx 272.396711 24.492879 0.000585 >> eqgre tm 172.63264 4.291884 0.001781 >> eqgre tm 189.441097 14.425498 0.001347 >> eqgre tm 170.743788 13.564472 0.000602 >> eqgre tm 158.960849 10.385299 0.001189 >> eqgre tm 80.972408 3.828254 0.000644 >> gicam tx 294.494001 9.656738 0.000524 >> gicam tx 267.126765 19.128024 0.000647 >> gicam tx 81.888658 4.782006 0.000492 >> gicam tx 168.32908 12.729939 0.001097 >> gicam tx 123.296056 7.007427 0.000659 >> gicam tm 94.264887 18.134533 0.000752 >> gicam tm 54.317395 3.828254 0.00038 >> gicam tm 55.978883 17.167534 0.000141 >> gicam tm 279.597993 15.313017 0.000398 >> gicam tm 288.262556 18.134533 0.001043 >> >> What I do next is: >> ---- >> list_Asfc<- list() >> list_Asfc[[1]]<- ssfamed[ssfamed$SPECSHOR=='cotau'&ssfamed$BONE=='tx', 3] >> list_Asfc[[2]]<- ssfamed[ssfamed$SPECSHOR=='cotau'&ssfamed$BONE=='tm', 3] >> ---- >> >> And so on for each level of SPECSHOR and BONE >> >> I'm stuck on 2 parts: >> - in a loop or something similar, I would like the 1st element of the >> list to be filled by the values for the 1st variable with the first >> level of my factors (i.e. cotau + tx), and then the 2nd element with the >> 2nd level (i.e. cotau + tm) and so on. As shown above, I know how to do >> it if I enter manually the different levels, but I have no idea which >> function I should use so that each combination of factor will be used. >> See what I mean? >> >> - I would then like to run it in a loop or something for each variable. >> It is by itself not so complicated, but I don't know how to give the >> correct name to my list. I want the list containing the data for Asfc to >> be named "list_Asfc". >> Here is what I tried: >> ---- >> seq.num<- c(seq(3,5,1)) #the indexes of the variables >> for(i in 1:length(seq.num)) { >> k<- seq.num[i] >> name.num<- names(ssfamed)[k] >> list<- list() >> list[[1]]<- ssfamed[ssfamed$SPECSHOR=='cotau'&ssfamed$BONE=='tx', i] >> list[[2]]<- ssfamed[ssfamed$SPECSHOR=='cotau'&ssfamed$BONE=='tm', i] >> names(list)<- c("cotau_tx", "cotau_tm") #I have more and the 1st >> question should help me on that too >> } >> ---- >> After names(list) I need to insert something like: name_list<- list >> But I don't know how to give it the correct name. How do we change the >> name of an object? Or am I on the wrong path? >> >> Thank you in advance for your help. >> Ivan >> >> PS: if necessary: under Windows XP, R2.10. >> >> >> >> >> >> >> >> >> >> >> >> >> [[alternative HTML version deleted]] >> >> > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
