I am trying to get hourly totals, given 15-minute bins. s = seq(0, 95, 1) s = floor(s/4) # 0 0 0 0 1 1 1 1 2 2 2 2 3 3 3 3 4 . . .
> s [1] 0 0 0 0 1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4 5 5 5 5 6 [26] 6 6 6 7 7 7 7 8 8 8 8 9 9 9 9 10 10 10 10 11 11 11 11 12 12 [51] 12 12 13 13 13 13 14 14 14 14 15 15 15 15 16 16 16 16 17 17 17 17 18 18 18 [76] 18 19 19 19 19 20 20 20 20 21 21 21 21 22 22 22 22 23 23 23 23 > mode(d) [1] "list" > d 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 Sunday 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 Sunday 0 0 0 0 0 5 5 5 0 0 0 0 0 0 0 6 0 3 1 0 1 6 8 9 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 Sunday 7 9 10 5 0 1 0 1 1 1 0 0 0 1 0 0 7 10 9 9 11 11 8 8 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 Sunday 10 7 6 7 8 7 4 4 6 5 5 5 5 0 0 0 1 6 2 3 0 > x = aggregate(d, by=list(s), FUN="sum") Error in FUN(X[[1L]], ...) : arguments must have same length > length(s) [1] 96 > length(d) [1] 96 What am I doing wrong? Thanks in advance list, Jim Rome ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.