On Feb 7, 2010, at 1:32 PM, David Winsemius wrote:

You have a dataframe with 96 columns and a single row named "Sunday". My guess is that was not your intent. How did "d" come to exist?

But to answer your question:

> apply(d, 1, function(z) aggregate(z, by=list(s), FUN=sum) )
$Sunday
   Group.1  x
1        0  1
2        1  0
3        2  0
4        3  0
5        4  2
6        5  0
7        6  0
8        7  0
9        8 15
10       9  0
11      10  6
12      11  5
13      12 30
14      13 24
15      14  3
16      15  1
17      16  8
18      17 39
19      18 37
20      19 28
21      20 21
22      21 20
23      22  1
24      23 11


--
David.

On Feb 7, 2010, at 1:29 PM, James Rome wrote:

dput(d)
structure(list(`0` = 0, `1` = 1, `2` = 0, `3` = 0, `4` = 0, `5` = 0,
  `6` = 0, `7` = 0, `8` = 0, `9` = 0, `10` = 0, `11` = 0, `12` = 0,
  `13` = 0, `14` = 0, `15` = 0, `16` = 0, `17` = 2, `18` = 0,
  `19` = 0, `20` = 0, `21` = 0, `22` = 0, `23` = 0, `24` = 0,
  `25` = 0, `26` = 0, `27` = 0, `28` = 0, `29` = 0, `30` = 0,
  `31` = 0, `32` = 5, `33` = 5, `34` = 5, `35` = 0, `36` = 0,
  `37` = 0, `38` = 0, `39` = 0, `40` = 0, `41` = 0, `42` = 6,
  `43` = 0, `44` = 3, `45` = 1, `46` = 0, `47` = 1, `48` = 6,
  `49` = 8, `50` = 9, `51` = 7, `52` = 9, `53` = 10, `54` = 5,
  `55` = 0, `56` = 1, `57` = 0, `58` = 1, `59` = 1, `60` = 1,
  `61` = 0, `62` = 0, `63` = 0, `64` = 1, `65` = 0, `66` = 0,
  `67` = 7, `68` = 10, `69` = 9, `70` = 9, `71` = 11, `72` = 11,
  `73` = 8, `74` = 8, `75` = 10, `76` = 7, `77` = 6, `78` = 7,
  `79` = 8, `80` = 7, `81` = 4, `82` = 4, `83` = 6, `84` = 5,
  `85` = 5, `86` = 5, `87` = 5, `88` = 0, `89` = 0, `90` = 0,
  `91` = 1, `92` = 6, `93` = 2, `94` = 3, `95` = 0), .Names = c("0",
"1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12",
"13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23",
"24", "25", "26", "27", "28", "29", "30", "31", "32", "33", "34",
"35", "36", "37", "38", "39", "40", "41", "42", "43", "44", "45",
"46", "47", "48", "49", "50", "51", "52", "53", "54", "55", "56",
"57", "58", "59", "60", "61", "62", "63", "64", "65", "66", "67",
"68", "69", "70", "71", "72", "73", "74", "75", "76", "77", "78",
"79", "80", "81", "82", "83", "84", "85", "86", "87", "88", "89",
"90", "91", "92", "93", "94", "95"), row.names = "Sunday", class =
"data.frame")
On 2/7/2010 1:27 PM, David Winsemius wrote:
On Feb 7, 2010, at 1:08 PM, James Rome wrote:

I am trying to get hourly totals, given 15-minute bins.
s = seq(0, 95, 1)
s = floor(s/4) # 0 0 0 0 1 1 1 1 2 2 2 2 3 3 3 3 4 .
. .

s
[1] 0 0 0 0 1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4 5 5
5  5  6
[26] 6 6 6 7 7 7 7 8 8 8 8 9 9 9 9 10 10 10 10 11 11 11
11 12 12
[51] 12 12 13 13 13 13 14 14 14 14 15 15 15 15 16 16 16 16 17 17 17 17
18 18 18
[76] 18 19 19 19 19 20 20 20 20 21 21 21 21 22 22 22 22 23 23 23 23

mode(d)
[1] "list"
d
    0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
25 26
Sunday 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0
0  0
27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48
49 50
Sunday 0 0 0 0 0 5 5 5 0 0 0 0 0 0 0 6 0 3 1 0 1
6  8  9
51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72
73 74
Sunday 7 9 10 5 0 1 0 1 1 1 0 0 0 1 0 0 7 10 9 9 11
11  8  8
    75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95
Sunday 10 7 6 7 8 7 4 4 6 5 5 5 5 0 0 0 1 6 2 3 0
x = aggregate(d, by=list(s), FUN="sum")
Error in FUN(X[[1L]], ...) : arguments must have same length

I don't know what sort of error is occurring. You have not created a
posting that easily lets us see what sort of object "d" really is. (And
it is not being display as though it were a simple list.)

dput(d) would have allowed us to see what sort of attributes it has.
Your code works if one strips out the data and puts it into a vector.

s = seq(0, 95, 1)
s = floor(s/4)

d <- scan()
1: 0 1 0 0 0 0 0 0 0 0  0  0  0  0  0  0  0  2  0  0  0  0  0  0  0
26: 0  0
28: 0  0  0  0  0  5  5  5  0  0  0  0  0  0  0  6  0  3  1  0  1
49: 6  8  9
52: 7  9 10  5  0  1  0  1  1  1  0  0  0  1  0  0  7 10  9  9 11
73: 11  8  8
76: 10  7  6  7  8  7  4  4  6  5  5  5  5  0  0  0  1  6  2  3  0
97:
Read 96 items
x = aggregate(d, by=list(s), FUN="sum")
x
 Group.1  x
1        0  1
2        1  0
3        2  0
4        3  0
5        4  2
6        5  0
7        6  0
8        7  0
9        8 15
10       9  0
11      10  6
12      11  5
13      12 30
14      13 24
15      14  3
16      15  1
17      16  8
18      17 39
19      18 37
20      19 28
21      20 21
22      21 20
23      22  1
24      23 11

length(s)
[1] 96
length(d)
[1] 96

What am I doing wrong?

Thanks in advance list,
Jim Rome

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

David Winsemius, MD
Heritage Laboratories
West Hartford, CT



David Winsemius, MD
Heritage Laboratories
West Hartford, CT

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

David Winsemius, MD
Heritage Laboratories
West Hartford, CT

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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