James, I think you want to try using index vectors. index <- c(1:length(x)) negs <- index[x<0] nonnegs <- index[x>=0]
Then, if you want the negative values, just use negativevalues <- x[negs] HTH steve [EMAIL PROTECTED] wrote: > Dear Mailing List, > > If I wanted a data set of twenty standard normal results, I would type: > > x<-rnorm(20) > > If I then wanted to make all the negative results in that data set to be > listed as zero I would then type in: > > x[x<0]<-0 > > However, I now want to discard the values that are zero, but I want to know > which values out of the original data set which I truncated to zeros I > discarded. How is the best way of doing this? Do I use match(x,0) / > (1:length(x))[x==0] ? How do I discard the values as well as wanting the > original data set values. All suggestions would be greatly appreciated. > > Thank you, > > James Hutton > > [[alternate HTML version deleted]] > > ______________________________________________ > [EMAIL PROTECTED] mailing list > http://www.stat.math.ethz.ch/mailman/listinfo/r-help ______________________________________________ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
