What are you using the data frame argument for?
If y, x1, x2, ..., xn were all the variables in the data frame all you need
do is
myfun <- function(y, dat) {
lm(y ~ ., dat)
}
but your question is very vague and ill-posed.
-----Original Message-----
From: Richard Nixon [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 03, 2003 2:50 AM
To: [EMAIL PROTECTED]
Subject: [R] lm with an arbitrary number of terms
Hello folks,
Any ideas how to do this?
data.frame is a data frame with column names "x1",...,"xn"
y is a response variable of length dim(data.frame)[1]
I want to write a function
function(y, data.frame){
lm(y~x1+...+xn)
}
This would be easy if n was always the same.
If n is arbitrary how could I feed the x1+...+xn terms into
lm(response~terms)?
Thanks
Richard
--
Dr. Richard Nixon
MRC Biostatistics Unit, Cambridge, UK
http://www.mrc-bsu.cam.ac.uk/personal/richard
Tel: +44 (0)1223 330382, Fax: +44 (0)1223 33038
______________________________________________
[EMAIL PROTECTED] mailing list
https://www.stat.math.ethz.ch/mailman/listinfo/r-help
______________________________________________
[EMAIL PROTECTED] mailing list
https://www.stat.math.ethz.ch/mailman/listinfo/r-help
