Prof. Riley has already answered this but I thought I would add
a bit more detail.
> # define a function chron.year.expand.0 with a different cutoff.
> # You can choose other cutoffs too but here we have chosen 0.
> chron.year.expand.0 <- function(x) year.expand(x,cut=0)
> # run chron -- we have not yet set the new year expansion
> chron("01/02/29", out.format="year-month-day")
[1] 2029-January-02
> # change the year expansion option to point to the new function
> options(chron.year.expand = "chron.year.expand.0")
> chron("01/02/29", out.format="year-month-day")
[1] 1929-January-02
> # now change it back
> options(chron.year.expand = "year.expand")
> chron("01/02/29", out.format="year-month-day")
[1] 2029-January-02
Date: Wed, 28 Jan 2004 11:50:11 +0100
From: Massimiliano Tripoli <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Subject: [R] Julian dates
Hi all,
I have problems with years of dates using "chron" package.
I don't understand why R by this istruction:
> dates("01/02/29",out.format="d/m/year")
[1] 02/Jan/2029
> dates("01/02/30",out.format="d/m/year")
[1] 02/Jan/1930
reads "29" as 2029
and "30" as 1930. How could I change to read "00" to "05" like 2000 to 2005 and "06"
to "99" like 1906 to 1999 ?
Thank you
Massimiliano
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