I left out the brackets in my last email but the problem
(a reappears after have been substituted out) still remains:
> z <- substitute( function(){a+1}, list(a=quote(b)) )
> z
function() {
b + 1
}
> eval(z)
function(){a+1}
---
Date: Wed, 17 Mar 2004 20:10:43 -0500 (EST)
From: Gabor Grothendieck <[EMAIL PROTECTED]>
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To: <[EMAIL PROTECTED]>
Subject: [R] substitute question
Consider the following example:
# substitute a with b in the indicated function. Seems to work.
> z <- substitute( function()a+1, list(a=quote(b)) )
> z
function() b + 1
# z is an object of class call so use eval
# to turn it into an object of class expression; however,
# when z is evaluated, the variable a returns.
> eval(z)
function()a+1
Why did a suddenly reappear again after it had already been replaced?
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