you could try this:
x <- factor(sample(letters[1:3], 20, TRUE))
#######
tab <- table(x)
names(tab)[tab == max(tab)]
I hope it helps.
Best,
Dimitris
----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/16/336899
Fax: +32/16/337015
Web: http://www.med.kuleuven.ac.be/biostat/
http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm
----- Original Message -----
From: "Rajarshi Guha" <[EMAIL PROTECTED]>
To: "R" <r-help@stat.math.ethz.ch>
Sent: Thursday, May 26, 2005 4:36 PM
Subject: [R] a more elegant approach to getting the majority level
Hi, I have a factor and I would like to find the most frequent
level.
I think my current approach is a bit long winded and I was wondering
if
there was a more elegant way to do it:
x <- factor(sample(1:0, 5,replace=TRUE))
levels(x)[ which( as.logical((table(x) == max(table(x)))) ==
TRUE ) ]
(The length of x will always be an odd number, so I wont get a tie
in
max())
Thanks,
-------------------------------------------------------------------
Rajarshi Guha <[EMAIL PROTECTED]> <http://jijo.cjb.net>
GPG Fingerprint: 0CCA 8EE2 2EEB 25E2 AB04 06F7 1BB9 E634 9B87 56EE
-------------------------------------------------------------------
Alcohol, an alternative to your self
- 'Alcohol' by the Bare Naked Ladies
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