You could also use: > names(rev(sort(table(x))))[1]
There is nonetheless a difference if there are several levels which provides this maximum. This method will only return one, yours would return all those levels (which may not be desirable for some others processing). HTH, Eric Eric Lecoutre UCL / Institut de Statistique Voie du Roman Pays, 20 1348 Louvain-la-Neuve Belgium tel: (+32)(0)10473050 [EMAIL PROTECTED] http://www.stat.ucl.ac.be/ISpersonnel/lecoutre If the statistics are boring, then you've got the wrong numbers. -Edward Tufte > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of Rajarshi Guha > Sent: jeudi 26 mai 2005 16:37 > To: R > Subject: [R] a more elegant approach to getting the majority level > > > Hi, I have a factor and I would like to find the most frequent level. > > I think my current approach is a bit long winded and I was > wondering if there was a more elegant way to do it: > > x <- factor(sample(1:0, 5,replace=TRUE)) > > levels(x)[ which( as.logical((table(x) == max(table(x)))) == TRUE ) ] > > (The length of x will always be an odd number, so I wont get a tie in > max()) > > Thanks, > > ------------------------------------------------------------------- > Rajarshi Guha <[EMAIL PROTECTED]> <http://jijo.cjb.net> > GPG Fingerprint: 0CCA 8EE2 2EEB 25E2 AB04 06F7 1BB9 E634 9B87 56EE > ------------------------------------------------------------------- > Alcohol, an alternative to your self > - 'Alcohol' by the Bare Naked Ladies > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! > http://www.R-project.org/posting-guide.html > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
