> > Here are a few alternatives: > > replace(a, is.na(a), 0) + b > > ifelse(is.na(a), 0, a) + b > > mapply(sum, a, b, MoreArgs = list(na.rm = TRUE)) >
Well, Gabor, if you want to get fancy...
evalq({a[is.na(a)]<-0;a})+b
(and variants...)
Cheers,
Bert
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