Quoting John Cowan and then Ray Dillinger:
Ray Dillinger scripsit:
> As an aside, I'm interested in how this function is
implemented.
It probably notices that 1/3 is the reciprocal of an integer,
and applies an exact method. (expt 27 2/3) returns
8.999999999999998.
To answer Ray, if you have (expt x p/q) and x is a positive fixnum,
bignum, or ratnum, it takes the qth root of x and sees if it's exact; if
so, it computes (expt (expt x 1/q) p).
And I don't know what John's talking about:
heine:~/programs/gambc-v4_5_2-devel> gsi
Gambit v4.5.2
> (expt 27 2/3)
9
Brad
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