Hallo,
On 9/23/09, Shiro Kawai <[email protected]> wrote:
>
> He used bitwise rotate. The paper is here, though it is in Japanese:
> http://www.nue.riec.tohoku.ac.jp/ppl2008/proceedings/1-17.pdf
>
> In short, when the exponent falls in "middle range", i.e. 512<e<1535,
> (b62 xor b61) == 1. If you rotate the word 3 bits to left, these
> two bits comes to LSB. He uses LSB==1 to mark this rotated double
> representation. See the code on the page 5.
>
Thanks!
--
-alex
http://www.ventonegro.org/
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