Sometimes, if the parser is having a problem interpreting what is stated,
you can substitute a variable which internally has the correct parameter.
SET VAR .vMT TEXT = ''
(SRPL(FirstName,'.',.vMT,0))
Does this make it work?
RRR

----- Original Message -----
From: "Richard Starkey" <[EMAIL PROTECTED]>
To: "Rbase-L" <[EMAIL PROTECTED]>
Sent: Tuesday, May 21, 2002 12:25 PM
Subject: Help with Function


> Hello All,
>
> How would you go about replacing a '.' without using the space ' ' in the
> (SRPL(0)) function.
> I have Imported Data in the table that looks like this:
>
> Mr. & Mrs. A.
> George C. & Linda V.
>
> I want it to look like this:
>
> Mr & Mrs A  --- No punctuation and no additional spaces
> George C & Linda V  --- No punctuation and no additional spaces
>
> Following is the statement I used:
> Update Person set FirstName = (SRPL(FirstName,'.','',0)) Where FirstName
> contains '.'
>
> I receive the following error message " -Error- Argument 3 of function
SRPL
> cannot be INTEGER. (2153)" Third argument is two single quotes.
>
> When I use the following statement the function works, however I have an
> additional space in the data. Third argument no has a space between the
> single quotes.
>
> Update Person set FirstName = (SRPL(FirstName,'.',' ',0)) Where FirstName
> contains '.'  There is an extra space between Mr,Mrs and A
> I cannot have a double space between the characters. (Mr__& Mrs__ A_)
>
>
> Any help would be appreciated.
>
> Rich ( RINGO) Starkey
>
>
>
>
>
>
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