Steve, I think worst case:
Set v vSecs = + ((dextract(.DateTime2)-dextract(.DateTime1))*86400)++ (textract(.DateTime2)-textract(.DateTime1))) Ben Petersen p.s. 86,400 = secs per day On 17 Oct 2002, at 12:46, Steve Durham wrote: > > > What would be the best way to find the difference between two DATETIME > variables in Rbase 6.5++? I need to be able to take the difference of > those two variables and break the difference down to a total of > seconds. I have a few ideas, but I am sure someone knows an easier way > to do this. > > > _________________________________________________________________ > Broadband?�Dial-up? Get reliable MSN Internet Access. > http://resourcecenter.msn.com/access/plans/default.asp > > ================================================ > TO SEE MESSAGE POSTING GUIDELINES: > Send a plain text email to [EMAIL PROTECTED] > In the message body, put just two words: INTRO rbase-l > ================================================ > TO UNSUBSCRIBE: send a plain text email to [EMAIL PROTECTED] In > the message body, put just two words: UNSUBSCRIBE rbase-l > ================================================ TO SEARCH ARCHIVES: > http://www.mail-archive.com/rbase-l%40sonetmail.com/ > ================================================ TO SEE MESSAGE POSTING GUIDELINES: Send a plain text email to [EMAIL PROTECTED] In the message body, put just two words: INTRO rbase-l ================================================ TO UNSUBSCRIBE: send a plain text email to [EMAIL PROTECTED] In the message body, put just two words: UNSUBSCRIBE rbase-l ================================================ TO SEARCH ARCHIVES: http://www.mail-archive.com/rbase-l%40sonetmail.com/
