Wrenches
We always try to minimize in connection cables as well as home run cables to 
the shorted length possible, restating batteries to aid this should always be 
considered as well as positive and negative runs
Jerry


Sent via the Samsung Galaxy S™ III, an AT&T 4G LTE smartphone

<div>-------- Original message --------</div><div>From: Ray Walters 
<r...@solarray.com> </div><div>Date:06/29/2015  12:05 PM  (GMT-10:00) 
</div><div>To: RE-wrenches <re-wrenches@lists.re-wrenches.org> 
</div><div>Subject: Re: [RE-wrenches] Battery Bank to Inverter Wiring 
</div><div>
</div>This is fascinating because while I knew the DC cables had an AC  
component, I never realized how much inductance played in the volt drop to the 
inverter.  Thanks for bringing this to our attention     Jarmo.  
Which brings up another question based on Benn's question:  isn't the battery 
itself part of the inductive loop?  and would the lead inside and steel cases 
act to increase the inductance?  Should we consider changing battery layouts 
not just to shorten cable lengths, but to counter inductance in the batteries 
themselves?  If needed, we could actually wire the batteries to "twist" by 
putting every other 2 v cell in the opposite row.  
My guess is that it wouldn't be worth it, but I've been wrong many times.......

R.Ray Walters
CTO, Solarray, Inc
Nabcep Certified PV Installer, 
Licensed Master Electrician
Solar Design Engineer
303 505-8760
On 6/29/2015 3:55 PM, Benn Kilburn wrote:
What about when you have the (+) and (-) terminals at opposite ends of a larger 
battery bank?  Sure you can run the conductors side-by-side once they meet up 
on their way to the inverter, but would you consider the distance between the 
end terminals a "large loop"? 
Ideally the battery string is laid out so the end terminals are close together 
and close to the inverter, but this isn't always the case. 

Benn Kilburn
SkyFire Energy Inc. 
780-906-7807


On Jun 29, 2015, at 10:28 AM, jarmo.venalai...@schneider-electric.com wrote:

Hi: 

From the comments so far, it appears             that within the wrenches 
group, good practices are the rule and DC cables are kept side by side, so the 
problem I mentioned hasn't come up much. 

I have seen "large loop" battery cables a couple of times in solar installs 
myself out on islands way down south.  Also on boats/RV's/motor homes. 

Please keep the cable loop in mind when you do bench tests of inverters, as it 
may screw up the results and make it seem like there is something wrong with 
the inverter.           

JARMO
_____________________________________________________________________________________
 

Jarmo Venalainen  |   Schneider Electric                 |  Xantrex             
  Brand  |   CANADA  |   Sales Application Engineer 
Phone: +604-422-2528  |   Tech Support:             800-670-0707  |   Mobile: 
+604-505-0291 
Email: jarmo.venalai...@schneider-electric.com  |   Site: www.Xantrex.com  |   
Address: 3700 Gilmore Way, Burnaby, BC V5G4M1
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From:   "b...@midnitesolar.com"                     <b...@midnitesolar.com>     
            
To:     RE-wrenches <re-wrenches@lists.re-wrenches.org>,
Date:   06/28/2015 10:30 PM
Subject:                        Re: [RE-wrenches] Battery Bank to Inverter 
Wiring
Sent by:                        "RE-wrenches" 
<re-wrenches-boun...@lists.re-wrenches.org>




On 6/28/2015 9:20 AM, Allan Sindelar wrote:
>>>>I'm not an EE, but I can't see what difference twisting would make in
the absence of a building/collapsing field as is normal with AC.<<<<

It is little known that with the typical inverters that use the heavy power 
transformers,
have a lot of AC 120 Hz (or 100 Hz for 50 Hz systems) current mixed in with 
that DC battery current.

The AC output current reflects back to the input as ripple current.  This is 
why you want to
have at least short as possible Sbattery cable runs AND keep the wires as close 
together as possible.

Twisting the battery cables may help a bit but that is probably overkill.

The problem has to do with inductance in the battery cables. You can use as big 
of cable
as you can fit in to reduce resistance, but that will not             help to 
lower the inductance.
The problems you can sometimes have with high inductance is             that 
L-C resonance at the
inverter can raise the peak voltages seen at the inverter input terminals and 
can be hard on
the inverter.

Then again,  the high frequency, lighter weight inverters will typically keep 
most of that ripple
inside,  between the DC input and AC output and battery cable inductance will 
not be as much
of a problem on the battery cables.

boB Gudgel




On 6/28/2015 9:20 AM, Allan Sindelar wrote: 
As a matter of course I have always run the             positive and negative 
conductors of high-current cable pairs together, but have never deliberately 
twisted them, and have never known of any related problems. 
The most obvious example of this would be 4/0             battery/inverter 
cables in a 24V system, with a 250A GJ-class breaker or (prior to that) a 300A 
or 400A Class T fuse. It's pretty tough to thread a twisted pair of 4/0 
USE/RHH/RHW cables through a 2" elbow or LB from inverter enclosure to battery 
enclosure.
I'm not an EE, but I can't see what difference twisting would make in the 
absence of a building/collapsing field as is normal with AC. 
I have twisted AC conductors together in the past when clients have expressed 
concerns about EMF from their equipment and wiring, but only AC.
Allan
Allan Sindelar
al...@sindelarsolar.com
NABCEP Certified PV Installation Professional
NABCEP Certified Technical Sales Professional
New Mexico EE98J Journeyman Electrician
Founder (Retired), Positive Energy, Inc.
505 780-2738 cell

 

On 6/27/2015 2:40 AM, John wrote: 
That is why for years we have               been twisting               those 
leads around each other.  I was told it was to               cancel out the 
opposing fields on the wires, but for whatever the correct technical reason     
          is,  we have always twisted those heavy wires.                       
John V.             
  
From: RE-wrenches [mailto:re-wrenches-boun...@lists.re-wrenches.org] On Behalf 
Of jarmo.venalai...@schneider-electric.com
Sent: Saturday, 27 June 2015 5:45 a.m.
To: RE-wrenches
Subject: [RE-wrenches] Battery Bank to Inverter Wiring 
  
Hi: 

From time to time over the years I've come across systems where the routing of 
DC cables between the batteries and the inverter has been the cause of  issues. 

I'm not referring to wire thickness or quality of terminations.  For the 
purposes of this discussion, just assume that wire               thickness and 
terminations are perfect.               

What I am referring to is the routing of the positive and negative battery 
cables.  In particular, the loop area within the + and - cables as shown in the 
image below, 

The problem I've seen in systems with a large loop in the setup is that the 
inverter does not provide good surge power and can               even go into 
low               voltage shutdown during large surges. 

Recently this happened again and I wanted to get a better feel for it, so I did 
some math.   

For a cable length of about 12', the loop is an inductor which has a value of 
inductance of about 1 uH for side by side cables and as much as 6 uH for cables 
about 1 foot apart.   

This inductance is greatly multiplied by any ferrous metal in the loop          
     and can easily be in the range of 10's to 100's of uH.  Examples being 
cables which run in steel conduits or along the steel               frame of a 
motor               home. 

Inductance causes a voltage drop proportional to the rate at which the current 
is changing.  To get an idea of how large that rate can be for typical 
inverters, I did surge tests with a 5kW inverter and found that the rate of 
change of current can be as high as 100A               per milli-second or 
100,000 Amps/second. 

Given that, the voltage drop of the wire inductance is then , Vdrop = (rate of 
change of current) x (inductance), 

Vdrop for 1 uH = (100,000 A/s) x (0.000001 H) = 0.1V 
Vdrop for 10 uH = (100,000 A/s) x (0.000001 H) = 1.0V 
Vdrop for 100 uH = (100,000 A/s) x (0.000001 H) = 10.0V    clearly this is a 
problem. 

Have any of the wrenches had systems with this issue?  If so, how often. 


JARMO




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