Let b be a block containing your session times. >> b: [1:00:21 2:00 3:30] == [1:00:21 2:00 3:30]
>> t: 0:0 ; total == 0:00 >> foreach time b [t: t + time] == 6:30:21 >> t / length? b == 2:10:07 Anton. > I have a series of times which represents session durations of users. > > They are in the format dd:hh:mm > > What I want to figure out is how long the average session takes. > > Do I have to parse out the days and hours into minutes and then > work out the average that way and then convert the result back > into dd:hh:mm or does someone know of a better way? > > Stuart -- To unsubscribe from this list, just send an email to [EMAIL PROTECTED] with unsubscribe as the subject.
