On Tue, Jan 02, 2001 at 09:55:23PM -0800, [EMAIL PROTECTED] wrote: > I have a list of space delimited filenames in a variable 'flist', and I > want to remove one of them which is in a variable 'fn'. ... > ... Do echo $flist | sed -e "s/ $fn / /" Note the included delimiters on either side of the variable, and the retention of one delimiter in the substitution string. You could also use 'awk'. Cheers, -- Dave Ihnat [EMAIL PROTECTED] _______________________________________________ Redhat-list mailing list [EMAIL PROTECTED] https://listman.redhat.com/mailman/listinfo/redhat-list
- Whole word substitution with sed bdoster
- Re: Whole word substitution with sed Statux
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- Re: upgrading to pine 4.30 Wolfgang Pfeiffer
- Re: upgrading to pine 4.30 Wolfgang Pfeiffer
- Re: upgrading to pine 4.30 Mike Burger
- Re: Whole word substitution with sed Luke C Gavel
- Re: Whole word substitution with sed Dave Ihnat
- Re: Whole word substitution with sed Anthony E . Greene
- RE: Whole word substitution with sed bdoster
- RE: Whole word substitution with sed bdoster
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- RE: Whole word substitution with sed Brad Doster
- Re: Whole word substitution with sed Cameron Simpson
- RE: Whole word substitution with sed Brad Doster
- NET: ? messages suppressed Ian Dobson