> flist=`echo "$flist" | sed -e 's/\ '$fn'\ / /' `
Thanks. That works with one additional modification - instead of…
flist="abcde bc de"
…if I use…
flist=". abcde bc de ."
…then it works! The premise for my script is that the current directory (.)
will never be in my file list, so $fn will never be = ".".
Some rules about bash (and perhaps other shell) variables I've learned here
are:
1) Leading spaces in a variable are eaten, e.g. var=" abc" becomes "abc"
2) Same for trailing spaces, e.g. var="abc " becomes "abc"
3) Multiple spaces between words are reduced to a single space, e.g. var="a
b c" becomes "a b c"
Are there any docs that spell the above out, including an explanation as to
why it works that way? I've read lost (er, lots, although 'lost' is often
appropriate:) of man pages and HowTo's but haven't seen this mentioned
anywhere.
Thanks again!
bd
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]On Behalf Of Luke C Gavel
Sent: Wednesday, January 03, 2001 12:22 AM
To: Brad Doster
Cc: [EMAIL PROTECTED]
Subject: Re: Whole word substitution with sed
On Tue, 2 Jan 2001 [EMAIL PROTECTED] wrote:
> flist=`echo "$flist" | sed -e 's/'$fn'//' | awk '{ print }'`
>
(untested)
flist=`echo "$flist" | sed -e 's/\ '$fn'\ / /' `
^
|
[space]
-- Generated Signature --
Most general statements are false,
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-- Alexander Dumas
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